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4(x+4)=2(2x+5)
We move all terms to the left:
4(x+4)-(2(2x+5))=0
We multiply parentheses
4x-(2(2x+5))+16=0
We calculate terms in parentheses: -(2(2x+5)), so:We get rid of parentheses
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
4x-4x-10+16=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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