4(x+4)+3(x+2)=7x+22

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Solution for 4(x+4)+3(x+2)=7x+22 equation: 


Simplifying
4(x + 4) + 3(x + 2) = 7x + 22

Reorder the terms:
4(4 + x) + 3(x + 2) = 7x + 22
(4 * 4 + x * 4) + 3(x + 2) = 7x + 22
(16 + 4x) + 3(x + 2) = 7x + 22

Reorder the terms:
16 + 4x + 3(2 + x) = 7x + 22
16 + 4x + (2 * 3 + x * 3) = 7x + 22
16 + 4x + (6 + 3x) = 7x + 22

Reorder the terms:
16 + 6 + 4x + 3x = 7x + 22

Combine like terms: 16 + 6 = 22
22 + 4x + 3x = 7x + 22

Combine like terms: 4x + 3x = 7x
22 + 7x = 7x + 22

Reorder the terms:
22 + 7x = 22 + 7x

Add '-22' to each side of the equation.
22 + -22 + 7x = 22 + -22 + 7x

Combine like terms: 22 + -22 = 0
0 + 7x = 22 + -22 + 7x
7x = 22 + -22 + 7x

Combine like terms: 22 + -22 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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