4(x+35)+3(x+14)=35

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Solution for 4(x+35)+3(x+14)=35 equation: 



4(x+35)+3(x+14)=35

We move all terms to the left:

4(x+35)+3(x+14)-(35)=0

We multiply parentheses

4x+3x+140+42-35=0

We add all the numbers together, and all the variables

7x+147=0

We move all terms containing x to the left, all other terms to the right

7x=-147

x=-147/7

x=-21

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