4(x+3)=3x+12+x

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Solution for 4(x+3)=3x+12+x equation: 



4(x+3)=3x+12+x

We move all terms to the left:

4(x+3)-(3x+12+x)=0

We add all the numbers together, and all the variables

4(x+3)-(4x+12)=0

We multiply parentheses

4x-(4x+12)+12=0

We get rid of parentheses

4x-4x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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