4(x+3)=3(x+1)+x

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Solution for 4(x+3)=3(x+1)+x equation: 



4(x+3)=3(x+1)+x

We move all terms to the left:

4(x+3)-(3(x+1)+x)=0

We multiply parentheses

4x-(3(x+1)+x)+12=0



We calculate terms in parentheses: -(3(x+1)+x), so:

3(x+1)+x

We add all the numbers together, and all the variables

x+3(x+1)

We multiply parentheses

x+3x+3

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We get rid of parentheses

4x-4x-3+12=0

We add all the numbers together, and all the variables

9!=0

There is no solution for this equation

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