4(x+3)-5=27+9x

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Solution for 4(x+3)-5=27+9x equation: 



4(x+3)-5=27+9x

We move all terms to the left:

4(x+3)-5-(27+9x)=0

We add all the numbers together, and all the variables

4(x+3)-(9x+27)-5=0

We multiply parentheses

4x-(9x+27)+12-5=0

We get rid of parentheses

4x-9x-27+12-5=0

We add all the numbers together, and all the variables

-5x-20=0

We move all terms containing x to the left, all other terms to the right

-5x=20

x=20/-5

x=-4

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