4(x+3)-4=(1/2x+1

Solution for 4(x+3)-4=(1/2x+1 equation:

4(x+3)-4=(1/2x+1

We move all terms to the left:

4(x+3)-4-((1/2x+1)=0


Domain of the equation: 2x+1)-4!=0

x∈R


We multiply parentheses

4x-((1/2x+1)-4+12=0

We multiply all the terms by the denominator


4x*2x+1)-4+12-((1=0

We add all the numbers together, and all the variables

4x*2x=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$