4(x+3)+x=3(x+4)+1

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Solution for 4(x+3)+x=3(x+4)+1 equation: 



4(x+3)+x=3(x+4)+1

We move all terms to the left:

4(x+3)+x-(3(x+4)+1)=0

We add all the numbers together, and all the variables

x+4(x+3)-(3(x+4)+1)=0

We multiply parentheses

x+4x-(3(x+4)+1)+12=0



We calculate terms in parentheses: -(3(x+4)+1), so:

3(x+4)+1

We multiply parentheses

3x+12+1

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We add all the numbers together, and all the variables

5x-(3x+13)+12=0

We get rid of parentheses

5x-3x-13+12=0

We add all the numbers together, and all the variables

2x-1=0

We move all terms containing x to the left, all other terms to the right

2x=1

x=1/2

x=1/2

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