4(x+3)+6=3x-(x+2)

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Solution for 4(x+3)+6=3x-(x+2) equation:



4(x+3)+6=3x-(x+2)
We move all terms to the left:
4(x+3)+6-(3x-(x+2))=0
We multiply parentheses
4x-(3x-(x+2))+12+6=0
We calculate terms in parentheses: -(3x-(x+2)), so:
3x-(x+2)
We get rid of parentheses
3x-x-2
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
We add all the numbers together, and all the variables
4x-(2x-2)+18=0
We get rid of parentheses
4x-2x+2+18=0
We add all the numbers together, and all the variables
2x+20=0
We move all terms containing x to the left, all other terms to the right
2x=-20
x=-20/2
x=-10

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