4(x+3)+6=2(x+1)

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Solution for 4(x+3)+6=2(x+1) equation: 



4(x+3)+6=2(x+1)

We move all terms to the left:

4(x+3)+6-(2(x+1))=0

We multiply parentheses

4x-(2(x+1))+12+6=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

4x-(2x+2)+18=0

We get rid of parentheses

4x-2x-2+18=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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