4(x+3)+5(x-4)=x+8

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Solution for 4(x+3)+5(x-4)=x+8 equation:



4(x+3)+5(x-4)=x+8
We move all terms to the left:
4(x+3)+5(x-4)-(x+8)=0
We multiply parentheses
4x+5x-(x+8)+12-20=0
We get rid of parentheses
4x+5x-x-8+12-20=0
We add all the numbers together, and all the variables
8x-16=0
We move all terms containing x to the left, all other terms to the right
8x=16
x=16/8
x=2

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