4(x+3)+2x=7(x-2)-6

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Solution for 4(x+3)+2x=7(x-2)-6 equation: 



4(x+3)+2x=7(x-2)-6

We move all terms to the left:

4(x+3)+2x-(7(x-2)-6)=0

We add all the numbers together, and all the variables

2x+4(x+3)-(7(x-2)-6)=0

We multiply parentheses

2x+4x-(7(x-2)-6)+12=0



We calculate terms in parentheses: -(7(x-2)-6), so:

7(x-2)-6

We multiply parentheses

7x-14-6

We add all the numbers together, and all the variables

7x-20

Back to the equation:

-(7x-20)



We add all the numbers together, and all the variables

6x-(7x-20)+12=0

We get rid of parentheses

6x-7x+20+12=0

We add all the numbers together, and all the variables

-1x+32=0

We move all terms containing x to the left, all other terms to the right

-x=-32

x=-32/-1

x=+32

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