4(x+3)+2(3x-5)=27

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Solution for 4(x+3)+2(3x-5)=27 equation: 



4(x+3)+2(3x-5)=27

We move all terms to the left:

4(x+3)+2(3x-5)-(27)=0

We multiply parentheses

4x+6x+12-10-27=0

We add all the numbers together, and all the variables

10x-25=0

We move all terms containing x to the left, all other terms to the right

10x=25

x=25/10

x=2+1/2

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