4(x+3)+12=20

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Solution for 4(x+3)+12=20 equation: 



4(x+3)+12=20

We move all terms to the left:

4(x+3)+12-(20)=0

We add all the numbers together, and all the variables

4(x+3)-8=0

We multiply parentheses

4x+12-8=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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