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4(x+2)=4(2-x)
We move all terms to the left:
4(x+2)-(4(2-x))=0
We add all the numbers together, and all the variables
4(x+2)-(4(-1x+2))=0
We multiply parentheses
4x-(4(-1x+2))+8=0
We calculate terms in parentheses: -(4(-1x+2)), so:We get rid of parentheses
4(-1x+2)
We multiply parentheses
-4x+8
Back to the equation:
-(-4x+8)
4x+4x-8+8=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0
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