4(x+2)=20-6(x-3)

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Solution for 4(x+2)=20-6(x-3) equation: 



4(x+2)=20-6(x-3)

We move all terms to the left:

4(x+2)-(20-6(x-3))=0

We multiply parentheses

4x-(20-6(x-3))+8=0



We calculate terms in parentheses: -(20-6(x-3)), so:

20-6(x-3)

determiningTheFunctionDomain
-6(x-3)+20

We multiply parentheses

-6x+18+20

We add all the numbers together, and all the variables

-6x+38

Back to the equation:

-(-6x+38)



We get rid of parentheses

4x+6x-38+8=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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