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4(x+2)=2+2(x+3)
We move all terms to the left:
4(x+2)-(2+2(x+3))=0
We multiply parentheses
4x-(2+2(x+3))+8=0
We calculate terms in parentheses: -(2+2(x+3)), so:We get rid of parentheses
2+2(x+3)
determiningTheFunctionDomain 2(x+3)+2
We multiply parentheses
2x+6+2
We add all the numbers together, and all the variables
2x+8
Back to the equation:
-(2x+8)
4x-2x-8+8=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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