4(x+2)=2(2x-2)-(x-3)

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Solution for 4(x+2)=2(2x-2)-(x-3) equation: 



4(x+2)=2(2x-2)-(x-3)

We move all terms to the left:

4(x+2)-(2(2x-2)-(x-3))=0

We multiply parentheses

4x-(2(2x-2)-(x-3))+8=0



We calculate terms in parentheses: -(2(2x-2)-(x-3)), so:

2(2x-2)-(x-3)

We multiply parentheses

4x-(x-3)-4

We get rid of parentheses

4x-x+3-4

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We get rid of parentheses

4x-3x+1+8=0

We add all the numbers together, and all the variables

x+9=0

We move all terms containing x to the left, all other terms to the right

x=-9

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