4(x+2)=1x+0

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Solution for 4(x+2)=1x+0 equation: 



4(x+2)=1x+0

We move all terms to the left:

4(x+2)-(1x+0)=0

We add all the numbers together, and all the variables

4(x+2)-(+x)=0

We multiply parentheses

4x-(+x)+8=0

We get rid of parentheses

4x-x+8=0

We add all the numbers together, and all the variables

3x+8=0

We move all terms containing x to the left, all other terms to the right

3x=-8

x=-8/3

x=-2+2/3

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