4(x+2)-7=5(x-6)+29

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Solution for 4(x+2)-7=5(x-6)+29 equation: 



4(x+2)-7=5(x-6)+29

We move all terms to the left:

4(x+2)-7-(5(x-6)+29)=0

We multiply parentheses

4x-(5(x-6)+29)+8-7=0



We calculate terms in parentheses: -(5(x-6)+29), so:

5(x-6)+29

We multiply parentheses

5x-30+29

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)



We add all the numbers together, and all the variables

4x-(5x-1)+1=0

We get rid of parentheses

4x-5x+1+1=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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