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4(x+2)-6=6x-2(-1+x)
We move all terms to the left:
4(x+2)-6-(6x-2(-1+x))=0
We add all the numbers together, and all the variables
4(x+2)-(6x-2(x-1))-6=0
We multiply parentheses
4x-(6x-2(x-1))+8-6=0
We calculate terms in parentheses: -(6x-2(x-1)), so:We add all the numbers together, and all the variables
6x-2(x-1)
We multiply parentheses
6x-2x+2
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
4x-(4x+2)+2=0
We get rid of parentheses
4x-4x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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