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4(x+2)-5=3(x+1)
We move all terms to the left:
4(x+2)-5-(3(x+1))=0
We multiply parentheses
4x-(3(x+1))+8-5=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
4x-(3x+3)+3=0
We get rid of parentheses
4x-3x-3+3=0
We add all the numbers together, and all the variables
x=0
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