4(x+2)-3=7(x+1)-9-2(2x-4)

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Solution for 4(x+2)-3=7(x+1)-9-2(2x-4) equation: 



4(x+2)-3=7(x+1)-9-2(2x-4)

We move all terms to the left:

4(x+2)-3-(7(x+1)-9-2(2x-4))=0

We multiply parentheses

4x-(7(x+1)-9-2(2x-4))+8-3=0



We calculate terms in parentheses: -(7(x+1)-9-2(2x-4)), so:

7(x+1)-9-2(2x-4)

determiningTheFunctionDomain
7(x+1)-2(2x-4)-9

We multiply parentheses

7x-4x+7+8-9

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

4x-(3x+6)+5=0

We get rid of parentheses

4x-3x-6+5=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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