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4(x+2)-1=6x-2(-3+x)
We move all terms to the left:
4(x+2)-1-(6x-2(-3+x))=0
We add all the numbers together, and all the variables
4(x+2)-(6x-2(x-3))-1=0
We multiply parentheses
4x-(6x-2(x-3))+8-1=0
We calculate terms in parentheses: -(6x-2(x-3)), so:We add all the numbers together, and all the variables
6x-2(x-3)
We multiply parentheses
6x-2x+6
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
4x-(4x+6)+7=0
We get rid of parentheses
4x-4x-6+7=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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