4(x+2)-12=3(2x-4)

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Solution for 4(x+2)-12=3(2x-4) equation: 



4(x+2)-12=3(2x-4)

We move all terms to the left:

4(x+2)-12-(3(2x-4))=0

We multiply parentheses

4x-(3(2x-4))+8-12=0



We calculate terms in parentheses: -(3(2x-4)), so:

3(2x-4)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

4x-(6x-12)-4=0

We get rid of parentheses

4x-6x+12-4=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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