4(x+2)+x+1=2x-3+3(x-4)

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Solution for 4(x+2)+x+1=2x-3+3(x-4) equation:


Simplifying
4(x + 2) + x + 1 = 2x + -3 + 3(x + -4)

Reorder the terms:
4(2 + x) + x + 1 = 2x + -3 + 3(x + -4)
(2 * 4 + x * 4) + x + 1 = 2x + -3 + 3(x + -4)
(8 + 4x) + x + 1 = 2x + -3 + 3(x + -4)

Reorder the terms:
8 + 1 + 4x + x = 2x + -3 + 3(x + -4)

Combine like terms: 8 + 1 = 9
9 + 4x + x = 2x + -3 + 3(x + -4)

Combine like terms: 4x + x = 5x
9 + 5x = 2x + -3 + 3(x + -4)

Reorder the terms:
9 + 5x = 2x + -3 + 3(-4 + x)
9 + 5x = 2x + -3 + (-4 * 3 + x * 3)
9 + 5x = 2x + -3 + (-12 + 3x)

Reorder the terms:
9 + 5x = -3 + -12 + 2x + 3x

Combine like terms: -3 + -12 = -15
9 + 5x = -15 + 2x + 3x

Combine like terms: 2x + 3x = 5x
9 + 5x = -15 + 5x

Add '-5x' to each side of the equation.
9 + 5x + -5x = -15 + 5x + -5x

Combine like terms: 5x + -5x = 0
9 + 0 = -15 + 5x + -5x
9 = -15 + 5x + -5x

Combine like terms: 5x + -5x = 0
9 = -15 + 0
9 = -15

Solving
9 = -15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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