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4(x+2)+x+1=2x-2x-3+3(x+4)
We move all terms to the left:
4(x+2)+x+1-(2x-2x-3+3(x+4))=0
We add all the numbers together, and all the variables
x+4(x+2)-(2x-2x-3+3(x+4))+1=0
We multiply parentheses
x+4x-(2x-2x-3+3(x+4))+8+1=0
We calculate terms in parentheses: -(2x-2x-3+3(x+4)), so:We add all the numbers together, and all the variables
2x-2x-3+3(x+4)
determiningTheFunctionDomain 2x-2x+3(x+4)-3
We add all the numbers together, and all the variables
3(x+4)-3
We multiply parentheses
3x+12-3
We add all the numbers together, and all the variables
3x+9
Back to the equation:
-(3x+9)
5x-(3x+9)+9=0
We get rid of parentheses
5x-3x-9+9=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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