4(x+2)(x+2)-3(x+2)-7=0

Solution for 4(x+2)(x+2)-3(x+2)-7=0 equation:

4(x+2)(x+2)-3(x+2)-7=0

We multiply parentheses

4(x+2)(x+2)-3x-6-7=0

We multiply parentheses ..

4(+x^2+2x+2x+4)-3x-6-7=0

We add all the numbers together, and all the variables

4(+x^2+2x+2x+4)-3x-13=0

We multiply parentheses

4x^2+8x+8x-3x+16-13=0

We add all the numbers together, and all the variables

4x^2+13x+3=0

a = 4; b = 13; c = +3;
Δ = b2-4ac
Δ = 132-4·4·3
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-11}{2*4}=\frac{-24}{8}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+11}{2*4}=\frac{-2}{8}
=-1/4
$