4(x+1)=x+3(x+2)-2

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Solution for 4(x+1)=x+3(x+2)-2 equation: 


Simplifying
4(x + 1) = x + 3(x + 2) + -2

Reorder the terms:
4(1 + x) = x + 3(x + 2) + -2
(1 * 4 + x * 4) = x + 3(x + 2) + -2
(4 + 4x) = x + 3(x + 2) + -2

Reorder the terms:
4 + 4x = x + 3(2 + x) + -2
4 + 4x = x + (2 * 3 + x * 3) + -2
4 + 4x = x + (6 + 3x) + -2

Reorder the terms:
4 + 4x = 6 + -2 + x + 3x

Combine like terms: 6 + -2 = 4
4 + 4x = 4 + x + 3x

Combine like terms: x + 3x = 4x
4 + 4x = 4 + 4x

Add '-4' to each side of the equation.
4 + -4 + 4x = 4 + -4 + 4x

Combine like terms: 4 + -4 = 0
0 + 4x = 4 + -4 + 4x
4x = 4 + -4 + 4x

Combine like terms: 4 + -4 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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