4(x+1)=3(x+3)+8

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Solution for 4(x+1)=3(x+3)+8 equation: 



4(x+1)=3(x+3)+8

We move all terms to the left:

4(x+1)-(3(x+3)+8)=0

We multiply parentheses

4x-(3(x+3)+8)+4=0



We calculate terms in parentheses: -(3(x+3)+8), so:

3(x+3)+8

We multiply parentheses

3x+9+8

We add all the numbers together, and all the variables

3x+17

Back to the equation:

-(3x+17)



We get rid of parentheses

4x-3x-17+4=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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