4(x+1)=2(x+3)+x

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Solution for 4(x+1)=2(x+3)+x equation: 



4(x+1)=2(x+3)+x

We move all terms to the left:

4(x+1)-(2(x+3)+x)=0

We multiply parentheses

4x-(2(x+3)+x)+4=0



We calculate terms in parentheses: -(2(x+3)+x), so:

2(x+3)+x

We add all the numbers together, and all the variables

x+2(x+3)

We multiply parentheses

x+2x+6

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

4x-3x-6+4=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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