4(x+1)-3(x+3)=10(2-x)+6(x-5)

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Solution for 4(x+1)-3(x+3)=10(2-x)+6(x-5) equation: 



4(x+1)-3(x+3)=10(2-x)+6(x-5)

We move all terms to the left:

4(x+1)-3(x+3)-(10(2-x)+6(x-5))=0

We add all the numbers together, and all the variables

4(x+1)-3(x+3)-(10(-1x+2)+6(x-5))=0

We multiply parentheses

4x-3x-(10(-1x+2)+6(x-5))+4-9=0



We calculate terms in parentheses: -(10(-1x+2)+6(x-5)), so:

10(-1x+2)+6(x-5)

We multiply parentheses

-10x+6x+20-30

We add all the numbers together, and all the variables

-4x-10

Back to the equation:

-(-4x-10)



We add all the numbers together, and all the variables

x-(-4x-10)-5=0

We get rid of parentheses

x+4x+10-5=0

We add all the numbers together, and all the variables

5x+5=0

We move all terms containing x to the left, all other terms to the right

5x=-5

x=-5/5

x=-1

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