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4(x+1)+x=2(2x+2)+x
We move all terms to the left:
4(x+1)+x-(2(2x+2)+x)=0
We add all the numbers together, and all the variables
x+4(x+1)-(2(2x+2)+x)=0
We multiply parentheses
x+4x-(2(2x+2)+x)+4=0
We calculate terms in parentheses: -(2(2x+2)+x), so:We add all the numbers together, and all the variables
2(2x+2)+x
We add all the numbers together, and all the variables
x+2(2x+2)
We multiply parentheses
x+4x+4
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
5x-(5x+4)+4=0
We get rid of parentheses
5x-5x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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