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4(x+1)+6x=5(3+2x)
We move all terms to the left:
4(x+1)+6x-(5(3+2x))=0
We add all the numbers together, and all the variables
4(x+1)+6x-(5(2x+3))=0
We add all the numbers together, and all the variables
6x+4(x+1)-(5(2x+3))=0
We multiply parentheses
6x+4x-(5(2x+3))+4=0
We calculate terms in parentheses: -(5(2x+3)), so:We add all the numbers together, and all the variables
5(2x+3)
We multiply parentheses
10x+15
Back to the equation:
-(10x+15)
10x-(10x+15)+4=0
We get rid of parentheses
10x-10x-15+4=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation
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