4(x+1)+4x-1=19

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Solution for 4(x+1)+4x-1=19 equation: 



4(x+1)+4x-1=19

We move all terms to the left:

4(x+1)+4x-1-(19)=0

We add all the numbers together, and all the variables

4x+4(x+1)-20=0

We multiply parentheses

4x+4x+4-20=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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