4(x+1)+3=3(x-2)

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Solution for 4(x+1)+3=3(x-2) equation: 



4(x+1)+3=3(x-2)

We move all terms to the left:

4(x+1)+3-(3(x-2))=0

We multiply parentheses

4x-(3(x-2))+4+3=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

4x-(3x-6)+7=0

We get rid of parentheses

4x-3x+6+7=0

We add all the numbers together, and all the variables

x+13=0

We move all terms containing x to the left, all other terms to the right

x=-13

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