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4(x+1)+3(2x-5)=59
We move all terms to the left:
4(x+1)+3(2x-5)-(59)=0
We multiply parentheses
4x+6x+4-15-59=0
We add all the numbers together, and all the variables
10x-70=0
We move all terms containing x to the left, all other terms to the right
10x=70
x=70/10
x=7
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