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4(x+1)+2=2x+2(4+x)
We move all terms to the left:
4(x+1)+2-(2x+2(4+x))=0
We add all the numbers together, and all the variables
4(x+1)-(2x+2(x+4))+2=0
We multiply parentheses
4x-(2x+2(x+4))+4+2=0
We calculate terms in parentheses: -(2x+2(x+4)), so:We add all the numbers together, and all the variables
2x+2(x+4)
We multiply parentheses
2x+2x+8
We add all the numbers together, and all the variables
4x+8
Back to the equation:
-(4x+8)
4x-(4x+8)+6=0
We get rid of parentheses
4x-4x-8+6=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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