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4(x+1)+2(x-1)=x+2
We move all terms to the left:
4(x+1)+2(x-1)-(x+2)=0
We multiply parentheses
4x+2x-(x+2)+4-2=0
We get rid of parentheses
4x+2x-x-2+4-2=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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