4(x)=x2+7x-22

Solution for 4(x)=x2+7x-22 equation:

4(x)=x2+7x-22

We move all terms to the left:

4(x)-(x2+7x-22)=0

We add all the numbers together, and all the variables

-(+x^2+7x-22)+4x=0

We get rid of parentheses

-x^2-7x+4x+22=0

We add all the numbers together, and all the variables

-1x^2-3x+22=0

a = -1; b = -3; c = +22;
Δ = b2-4ac
Δ = -32-4·(-1)·22
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{97}}{2*-1}=\frac{3-\sqrt{97}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{97}}{2*-1}=\frac{3+\sqrt{97}}{-2}
$