4(w+2)=5(w-1)

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Solution for 4(w+2)=5(w-1) equation: 



4(w+2)=5(w-1)

We move all terms to the left:

4(w+2)-(5(w-1))=0

We multiply parentheses

4w-(5(w-1))+8=0



We calculate terms in parentheses: -(5(w-1)), so:

5(w-1)

We multiply parentheses

5w-5

Back to the equation:

-(5w-5)



We get rid of parentheses

4w-5w+5+8=0

We add all the numbers together, and all the variables

-1w+13=0

We move all terms containing w to the left, all other terms to the right

-w=-13

w=-13/-1

w=+13

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