4(w+2)(-w-3)=0

Solution for 4(w+2)(-w-3)=0 equation:

4(w+2)(-w-3)=0

We add all the numbers together, and all the variables

4(w+2)(-1w-3)=0

We multiply parentheses ..

4(-1w^2-3w-2w-6)=0

We multiply parentheses

-4w^2-12w-8w-24=0

We add all the numbers together, and all the variables

-4w^2-20w-24=0

a = -4; b = -20; c = -24;
Δ = b2-4ac
Δ = -202-4·(-4)·(-24)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4}{2*-4}=\frac{16}{-8}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4}{2*-4}=\frac{24}{-8}
=-3
$