4(v=1)+v=3(v-2)+2

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Solution for 4(v=1)+v=3(v-2)+2 equation: 



4(v=1)+v=3(v-2)+2

We move all terms to the left:

4(v-(1)+v)=0

We add all the numbers together, and all the variables

4(2v-1)=0

We multiply parentheses

8v-4=0

We move all terms containing v to the left, all other terms to the right

8v=4

v=4/8

v=1/2

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