4(v-9)-6=28v-28-6v

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Solution for 4(v-9)-6=28v-28-6v equation: 



4(v-9)-6=28v-28-6v

We move all terms to the left:

4(v-9)-6-(28v-28-6v)=0

We add all the numbers together, and all the variables

4(v-9)-(22v-28)-6=0

We multiply parentheses

4v-(22v-28)-36-6=0

We get rid of parentheses

4v-22v+28-36-6=0

We add all the numbers together, and all the variables

-18v-14=0

We move all terms containing v to the left, all other terms to the right

-18v=14

v=14/-18

v=-7/9

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