4(v-3)=6-2(v+1)

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Solution for 4(v-3)=6-2(v+1) equation: 



4(v-3)=6-2(v+1)

We move all terms to the left:

4(v-3)-(6-2(v+1))=0

We multiply parentheses

4v-(6-2(v+1))-12=0



We calculate terms in parentheses: -(6-2(v+1)), so:

6-2(v+1)

determiningTheFunctionDomain
-2(v+1)+6

We multiply parentheses

-2v-2+6

We add all the numbers together, and all the variables

-2v+4

Back to the equation:

-(-2v+4)



We get rid of parentheses

4v+2v-4-12=0

We add all the numbers together, and all the variables

6v-16=0

We move all terms containing v to the left, all other terms to the right

6v=16

v=16/6

v=2+2/3

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