4(v-1)=-(4v+5)-32

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Solution for 4(v-1)=-(4v+5)-32 equation: 



4(v-1)=-(4v+5)-32

We move all terms to the left:

4(v-1)-(-(4v+5)-32)=0

We multiply parentheses

4v-(-(4v+5)-32)-4=0



We calculate terms in parentheses: -(-(4v+5)-32), so:

-(4v+5)-32

We get rid of parentheses

-4v-5-32

We add all the numbers together, and all the variables

-4v-37

Back to the equation:

-(-4v-37)



We get rid of parentheses

4v+4v+37-4=0

We add all the numbers together, and all the variables

8v+33=0

We move all terms containing v to the left, all other terms to the right

8v=-33

v=-33/8

v=-4+1/8

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