4(v+6)=2v+42

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Solution for 4(v+6)=2v+42 equation: 



4(v+6)=2v+42

We move all terms to the left:

4(v+6)-(2v+42)=0

We multiply parentheses

4v-(2v+42)+24=0

We get rid of parentheses

4v-2v-42+24=0

We add all the numbers together, and all the variables

2v-18=0

We move all terms containing v to the left, all other terms to the right

2v=18

v=18/2

v=9

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