4(v+5)=7(v+5)+2v

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Solution for 4(v+5)=7(v+5)+2v equation: 



4(v+5)=7(v+5)+2v

We move all terms to the left:

4(v+5)-(7(v+5)+2v)=0

We multiply parentheses

4v-(7(v+5)+2v)+20=0



We calculate terms in parentheses: -(7(v+5)+2v), so:

7(v+5)+2v

We add all the numbers together, and all the variables

2v+7(v+5)

We multiply parentheses

2v+7v+35

We add all the numbers together, and all the variables

9v+35

Back to the equation:

-(9v+35)



We get rid of parentheses

4v-9v-35+20=0

We add all the numbers together, and all the variables

-5v-15=0

We move all terms containing v to the left, all other terms to the right

-5v=15

v=15/-5

v=-3

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