4(v+5)=2v+28

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Solution for 4(v+5)=2v+28 equation: 



4(v+5)=2v+28

We move all terms to the left:

4(v+5)-(2v+28)=0

We multiply parentheses

4v-(2v+28)+20=0

We get rid of parentheses

4v-2v-28+20=0

We add all the numbers together, and all the variables

2v-8=0

We move all terms containing v to the left, all other terms to the right

2v=8

v=8/2

v=4

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