4(v+5)=-4(2v-3)+2v

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Solution for 4(v+5)=-4(2v-3)+2v equation: 



4(v+5)=-4(2v-3)+2v

We move all terms to the left:

4(v+5)-(-4(2v-3)+2v)=0

We multiply parentheses

4v-(-4(2v-3)+2v)+20=0



We calculate terms in parentheses: -(-4(2v-3)+2v), so:

-4(2v-3)+2v

We add all the numbers together, and all the variables

2v-4(2v-3)

We multiply parentheses

2v-8v+12

We add all the numbers together, and all the variables

-6v+12

Back to the equation:

-(-6v+12)



We get rid of parentheses

4v+6v-12+20=0

We add all the numbers together, and all the variables

10v+8=0

We move all terms containing v to the left, all other terms to the right

10v=-8

v=-8/10

v=-4/5

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